5 - Lecture notes for Clay Mineralogy


Required reading:

Moore and Reynolds, Pages 77-103
Brindley and Brown, pages 128-135, 225-261


Theoretical treatment of X-ray Diffraction

It is possible to calculate the diffraction pattern (i.e., coherent interference pattern) for any given crystal structure given:


Miller Indices - a symbolic vector representation for the orientation of an atomic plane in a crystal lattice and are defined as the reciprocals of the fractional intercepts which the plane makes with the crystallographic axes. For more on Miller indices click here.


Scattering effects

Atoms scatter radiation (with a wavelength equal to that of incident radiation) in all directions (like a beacon). The efficiency (f) is the result of scattering from individual electrons.

f = Amplitude of a wave scattered by atom / Amplitude of wave scattered by an electron

Scattering efficiency is also controlled by direction of scattering.  The figure below shows the phase shift that results from scattering from two different regions of the electron cloud.



As a consequence,decreases with increasing angle of reflection. The figure below shows the change in f for commonly encountered ions in clay minerals. The atomic scattering factor values are plotted as a function of °2θ. The plot below is for Cu Kα radiation. Click here for an Excel spreadsheet that allows you to change the wavelength of radiation (data from Cullity, 1978).



Scattering from a unit cell

Recall that rows of atoms cause scatter in specific directions resulting in constructive interference (i.e., coherent scatter).

For the case of clay minerals, the approach is greatly simplified. The morphological nature of clay minerals is such that they can easily be prepared to orient their crystallographic axes (the ab plane) relative to the X-ray beam. This is called "preferred orientation" (as opposed to random orientation).

We now want to describe this diffraction effect from a unit cell in a crystal.  If the clays are oriented, then we can consider this to be a one-dimensional diffraction problem.

The scattering from a unit cell (F) is always less than the total sum of atoms in the unit cell because the rays that the atoms scatter are out of phase with each other.   F is call the structure factor and is therefore, a measure of the intensity of the diffracted X-­ray beam.

To find F, the sum of the amplitudes of each atom in the unit cell must be determined.

The sum of amplitudes must be adjusted by the amount of phase difference due to the location of the atoms in the unit cell. Recall that the phase difference is related to (1) the wavelength, (2) the angle of incidence, (3) the position of the atom planes and (4) the number and type of atoms in each plane. An example is given the figure below.


Phase shift  φ can  be expressed in more common crytallographic variables.

If d is equal to the c lattice parameter, and x/c is the fractional coordinate w (recall also that (uvw) are the fractional coodinates for any position within a 3-D unit cell), then the phase shift expression becomes

φ = 2 π l w

For the 3-D case of (hkl)

φ = 2 π (h u + k v + l w)

Phase differences between the scattered waves (all with the same wavelength) can be determined mathematically by a structure factor function where:

F = Σnf nexp(i φn) = f exp(i φ1) + f exp(i φ2) + ... f exp(i φn)

where:

We use the identity:

exp(i φn) = cos φn + i sinφn

to yield

F = Σn fn cosφn + i Σn fn sinφn

If there is a center of symmetry in the unit cell and the origin for the calculation can be placed at that point then the sine series goes to zero and the complex number is eliminated. This elimination is not essential to the theoretical development of the structure factor. It's just being elminated here to help streamline the example and simplify the calculations.

Therefore the above equation becomes,

F = Σn fn cosφn

We can expand the phase of the wave (φn) by letting

φn = 2πl (zn/c)

where:

let:

F = ΣnPn fn cos[2πl (zn/c)]

The fact that F can be negative or positive is not detectable in the X-ray experiment. The only thing that we measure with a detector is the intensity or magnitude. Therefore, squaring F eliminates its sign. What the detectors sees then is |F|2 .

F is a discontinuous function (i.e., it is defined by the integer l).

In order to consider the structure factor over a range of angular space (i.e., make it a continuous function) we return to Bragg's Law.

nλ = 2d sin θ

let:

solve in terms of l

l = 2 c sin θ/ λ

by substitution:

G = Σn Pn fn cos[4π zn(sinθ/λ)]

Where:

 

The interference function (φ)

Under ideal conditions all the diffraction takes place at the Bragg angles of reflection.

Diffraction effects (in one dimension) due to scattering from a grating can be described by an interference function:

where:

If N = 1 then Φ = 1 at all angles. Bragg reflection cannot occur from a single scattering center.

If N = 100, then Φ (at the ideal Bragg angle) is large. At the same time φ is small away from the Bragg angle. In other words the peaks are very intense and narrow.

The example below are graphical solutions to the interference function using values of 8° 2θ, λ = 1.54049 Å and various values of N.



Click here for an Excel spreadsheet that will let you play with the variables N, D, and λ

Lorentz-Polarization factors (Lp)

Polarization factor (p)- The X-ray beam that exits the tube is unpolarized (analagous to light coming from the sun).  Low angle scattering causes polarization of the beam (analgous to light reflecting off a lake). The polarization factor accounts for increase scattering at low angles. Various workers have conducted experiments and fit their results to theory and found the scattering intensity (Ip) due to polarization is proportional to (1 + cos2  θ)/2. This is taken from theoretical study and is known as the Thomson equation for scattering of an X-ray beam from a single electron. 

Lorentz factor (L)- The X-ray beam that exits the tube is also not strictly monochromatic nor parallel (some divergence occurs). These factors in combination with motion of the crystal (as noted by Klug and Alexander) contribute to a planes "opportunity" to reflect (i.e, planes that make an angle with the rotation axis are in a reflecting position longer than those parallel to the axis, hence disproptionate intensities will be observed).  The Lorentz factor is related to the volume of sample irradiated as a function of angle.

The number of crystals exposed to the beam is also a factor. Therefore we need to consider scattered beams from random powders differently from single crystals.  The single crystal form of the Lorentz factor is sin 2&theta. The random powder form of the Lorentz factor is (sin θ sin 2θ). We will see later, that from a practical standpoint it is almost impossible to achieve a perfectly oriented sample or a complete randomly oriented sample. The approach will be to use some mixture or blending of the single crystal form and the powder ring distribution factor (ψ).  Lp = (1 + cos2  θ) ψ / (sin θ). For random powders ψ is propotional to 1/(sin θ). For a single crystal ψ is constant. The development of this theory is given by Reynolds (1986).


If you really want to know a lot more about L-P factors, then seek the reference below.

Reynolds R. C. (1986) The lorentz-polarization factor and preferred oreinetation in oriented clay aggregates: Clays and Clay Minerals 34(4), 359-367.


Effect of scattering domain size and defects

A characteristic of clay minerals is that size of their coherent scattering domains is typically small and there are imperfections or stacking defects between adjacent domains (i.e. N is small).

The result of numerous stacking faults or small domain sizes is known as particle size broadening and can be inferred from the peak widths (as seen in the interference function above).

Peak widths are measures by their Full Widths at Maximum Half-height (FWMH).

Under certain conditions the FWMH can be used to estimate the distribution of particle sizes (domain sizes, not particle diameters).

This is expressed by the Scherrer Equation which assumes all reflections along a line normal to the reflecting plane.

L =λ K / β cosθ

where:

Example:

let:

then:

L = (1.54059 x 1 ) / [(0.1 x 3.14 / 180) x cos (13.3°)] = 1300Å


Click here for a set of notes that discuss sources of XRD error